d_log = {1: 0, 2: 1, 4:2, 8:3, 16:4, 32:5, 64:6, 128:7, 256:8, 512:9}.get (rational_len.denominator (), -1)
# Duration of the form 1/2^n or 3/2^n can be converted to a simple lilypond duration
- if (d_log >= 0 and rational_len.numerator() in (1,3,5,7) ):
+ dots = {1: 0, 3: 1, 7: 2, 15: 3, 31: 4, 63: 5, 127: 6}.get (rational_len.numerator(), -1)
+ if ( d_log >= dots >= 0 ):
# account for the dots!
- d.dots = (rational_len.numerator()-1)/2
- d.duration_log = d_log - d.dots
+ d.duration_log = d_log - dots
+ d.dots = dots
elif (d_log >= 0):
d.duration_log = d_log
d.factor = Rational (rational_len.numerator ())