//sort seqs by number of identical seqs
sort(alignSeqs.begin(), alignSeqs.end(), comparePriority);
- //go through active list and cluster everthing you can, until all nodes are inactive
- //taking advantage of the fact that maps are already sorted
-// map<string, bool>::iterator itActive;
-// map<string, bool>::iterator it2Active;
int count = 0;
-
+
+ //think about running through twice...
for (int i = 0; i < numSeqs; i++) {
//are you active