if ((processToAssign-1) == 1) { m->mothurOut(distName[i].begin()->first + "\n"); }
}
- //not lets reverse the order of ever other process, so we balance big files running with little ones
+ //now lets reverse the order of ever other process, so we balance big files running with little ones
for (int i = 0; i < processors; i++) {
//cout << i << endl;
int remainder = ((i+1) % processors);