Issue 4626/2: Make some regtests use \= instead of their own definitions

diff --git a/input/regression/phrasing-slur-multiple.ly b/input/regression/phrasing-slur-multiple.ly
index 08487af5d9386df8b3381b87d4ed34d10f65235f..adf8221845b9a8077eca0c446bb161607f51aee3 100644 (file)
--- a/input/regression/phrasing-slur-multiple.ly
+++ b/input/regression/phrasing-slur-multiple.ly
@@ -1,4 +1,4 @@
-\version "2.19.22"
+\version "2.19.29"
 
 #(ly:set-option 'warning-as-error #f)
 #(ly:expect-warning (_ "already have phrasing slur"))
@@ -12,14 +12,10 @@ slur will not be generated.  However, one can can create a second slur with
 a different spanner-id."
 }
 
-sp=#(define-event-function (n e) (index? ly:event?)
-     (set! (ly:music-property e 'spanner-id) (format "sp~a" n))
-     e)
-
 \relative { 
   % This will give warnings ("Already have phrasing slur" and "Cannot end phrasing slur")
-  c''4\(\(\sp1\( d4\)\(\sp1\( e4\) f\) |
+  c''4\(\(\=1\( d4\)\(\=1\( e4\) f\) |
   % This will give two overlapping slurs and "unterminated phrasing slur" from above
-  d\(  d\sp2\( e\) f\sp2\) |
+  d\(  d\=2\( e\) f\=2\) |
   
 }

diff --git a/input/regression/slur-multiple.ly b/input/regression/slur-multiple.ly
index a5e8b38c6061885d878f8fa49eb7a222b1adef94..007b69773ec293a7d30af9d6043bda472b3fde3b 100644 (file)
--- a/input/regression/slur-multiple.ly
+++ b/input/regression/slur-multiple.ly
@@ -1,4 +1,4 @@
-\version "2.19.22"
+\version "2.19.29"
 
 #(ly:set-option 'warning-as-error #f)
 #(ly:expect-warning (_ "already have slur"))
@@ -12,14 +12,10 @@ slur will not be generated.  However, one can can create a second slur with
 a different spanner-id."
 }
 
-sp=#(define-event-function (n e) (index? ly:event?)
-     (set! (ly:music-property e 'spanner-id) (format "sp~a" n))
-     e)
-
 \relative { 
   % This will give warnings ("Already have slur" and "Cannot end slur")
-  c''4((\sp1( d4)(\sp1( e4) f) |
+  c''4((\=1( d4)(\=1( e4) f) |
   % This will give two overlapping slurs and "unterminated slur" from above
-  d(  d\sp2( e) f\sp2) |
+  d(  d\=2( e) f\=2) |
   
 }