From 34ab2dce170021ce3d2452dff699a9c95dbc35e5 Mon Sep 17 00:00:00 2001 From: don Date: Fri, 14 May 2010 02:15:48 +0000 Subject: [PATCH] update formalism git-svn-id: svn+ssh://hemlock.ucr.edu/srv/svn/misc/trunk/origins_of_life@497 25fa0111-c432-4dab-af88-9f31a2f6ac42 --- kinetic_formalism.Rnw | 25 ++++++++++++++++++++++--- 1 file changed, 22 insertions(+), 3 deletions(-) diff --git a/kinetic_formalism.Rnw b/kinetic_formalism.Rnw index 018c44e..1ed5a8b 100644 --- a/kinetic_formalism.Rnw +++ b/kinetic_formalism.Rnw @@ -67,11 +67,30 @@ require(grid) \section{State Equation} % double check this with the bits in the paper \begin{equation} - \frac{d C^{j}_{i_\mathrm{ves}}}{dt} = k_{fi}k_{fi\mathrm{adj}}\left[C^j_{i_\mathrm{monomer}}\right] - - k_{bi}k_{bi\mathrm{adj}}C^j_{i_\mathrm{ves}} + \frac{d C_{i_\mathrm{ves}}}{dt} = k_{fi}k_{fi\mathrm{adj}}\left[C_{i_\mathrm{monomer}}\right]S_\mathrm{ves} - + k_{bi}k_{bi\mathrm{adj}}C_{i_\mathrm{ves}} \label{eq:state} \end{equation} +For $k_{fi}k_{fi\mathrm{adj}}\left[C_{i_\mathrm{monomer}}\right]$, +$k_{fi}$ has units of $\frac{\mathrm{m}}{\mathrm{s}}$, +$k_{fi\mathrm{adj}}$ and $k_{bi\mathrm{adj}}$ are unitless, +concentration is in units of $\frac{\mathrm{n}}{\mathrm{L}}$, surface +area is in units of $\mathrm{m}^2$, $k_{bi}$ has units of +$\frac{1}{\mathrm{s}}$ and $C_{i_\mathrm{ves}}$ has units of +$\mathrm{n}$, Thus, we have + +\begin{equation} + \frac{\mathrm{n}}{\mathrm{s}} = \frac{\mathrm{m}}{\mathrm{s}} \frac{\mathrm{n}}{\mathrm{L}} \mathrm{m}^2 \frac{1000\mathrm{L}}{\mathrm{m}^3} - + \frac{1}{\mathrm{s}} \mathrm{n} + = + \frac{\mathrm{m^3}}{\mathrm{s}} \frac{\mathrm{n}}{\mathrm{L}} \frac{1000\mathrm{L}}{\mathrm{m}^3} - \frac{\mathrm{n}}{\mathrm{s}}= + \frac{\mathrm{n}}{\mathrm{s}} = 1000 \frac{\mathrm{n}}{\mathrm{s}} - \frac{\mathrm{n}}{\mathrm{s}} + \label{eq:state_units} +\end{equation} + +The 1000 isn't in \fref{eq:state} above, because it is unit-dependent. + \subsection{Forward adjustments ($k_{fi\mathrm{adj}}$)} \begin{equation} @@ -160,7 +179,7 @@ curve(3^x,from=0,to=sd(c(12,24)), \newpage \subsubsection{Unsaturation Backward} \begin{equation} - un_b = 10^{\left|3.5^{-\left}-3.5^{-\left}\right|} + un_b = 10^{\left|3.5^{-\left}-3.5^{-un_\mathrm{monomer}}\right|} \label{eq:unsaturation_backward} \end{equation} -- 2.39.2