% double check this with the bits in the paper
For a system with monomers $(_\mathrm{monomer})$ and a vesicle
-$(_\mathrm{vesicle})$, the change in composition of the $i$th component of
+$(_\mathrm{vesicle})$, the change in concentration of the $i$th component of
a lipid vesicle per change in time ($d \left[C_{i_\mathrm{vesicle}}\right]/dt$)
can be described by a modification of the basic mass action law:
formation is increased when the unsaturation of lipids in the vesicle
is widely distributed; in other words, the insertion of lipids into
the membrane is greater when the standard deviation of the
-unsaturation is larger %
+unsaturation is larger. %
%%% \RZ{May need to site (at least for us) works showing
%%% mismatch-dependent ``defects''}. %
Assuming that an increase in width of the distribution linearly
\end{equation}
The most common $\mathrm{stdev} l_\mathrm{vesicle}$ is around $3.4$, which leads to
-a range of $\Delta \Delta G^\ddagger$ of
+a $\Delta \Delta G^\ddagger$ of
$\Sexpr{format(digits=3,to.kcal(2^(3.4)))}
\frac{\mathrm{kcal}}{\mathrm{mol}}$.
does, the backwards rate constant adjustment $k_{\mathrm{b}i\mathrm{adj}}$
takes into account unsaturation ($un_\mathrm{b}$), charge ($ch_\mathrm{b}$), curvature
($cu_\mathrm{b}$), length ($l_\mathrm{b}$), and complex formation ($CF1_\mathrm{b}$), each of
-which are modified depending on the specific component and the vesicle
+which is modified depending on the specific component and the vesicle
from which the component is exiting:
\end{figure}
\subsubsection{Charge Backwards}
-As in the case of monomers entering a vesicle, monomers leaving a
-vesicle leave faster if their charge has the same sign as the average
-charge vesicle. An equation of the form $ch_\mathrm{b} = a^{\left<ch_v\right>
- ch_m}$ is then appropriate, and using a base of $a=20$ yields:
+As in the case of monomers entering a vesicle, opposites attract.
+Monomers leaving a vesicle leave faster if their charge has the same
+sign as the average charge vesicle. An equation of the form
+$ch_\mathrm{b} = a^{\left<ch_v\right> ch_m}$ is then appropriate, and
+using a base of $a=20$ yields:
\begin{equation}
ch_\mathrm{b} = 20^{\left<{ch}_v\right> {ch}_m}