- for (i in 2:length(x)) {
- if (identical(x[[i]]$tip.label, ref)) next
- ilab <- match(x[[i]]$tip.label, ref)
- ## can use tabulate here because 'ilab' contains integers
- if (any(tabulate(ilab) > 1))
- stop(paste("some tip labels are duplicated in tree no.", i))
- if (any(is.na(ilab)))
- stop(paste("tree no.", i, "has different tip labels"))
- ie <- match(1:n, x[[i]]$edge[, 2])
- x[[i]]$edge[ie, 2] <- ilab
+ Ntree <- length(x)
+ if (Ntree > 1) {
+ for (i in 2:Ntree) {
+ label <- x[[i]]$tip.label
+ if (!identical(label, ref)) {
+ if (length(label) != length(ref))
+ stop(paste("tree no.", i, "has a different number of tips"))
+ ilab <- match(label, ref)
+ ## can use tabulate here because 'ilab' contains integers
+ if (any(is.na(ilab)))
+ stop(paste("tree no.", i, "has different tip labels"))
+### <FIXME> the test below does not seem useful anymore
+### if (any(tabulate(ilab) > 1))
+### stop(paste("some tip labels are duplicated in tree no.", i))
+### </FIXME>
+ ie <- match(1:n, x[[i]]$edge[, 2])
+ x[[i]]$edge[ie, 2] <- ilab
+ }
+ x[[i]]$tip.label <- NULL
+ }